This answer is not correct. I think that you have reversed your logic.
Let's see what happens by using a simple fraction and changing one of the numbers. The fraction 1/2 = 0.5. If the 1 is changed to a 3, then the 2 must be changed to a 6 (3 times as much) in order for the fraction to still equal 0.5...(3/6 = 0.5). If you think in terms of a simple relationship like this, then it is easy to remember how this change takes place. Now try to answer the question...remember that you are changing the numerator of the fraction by increasing the amount of calcium phosphate. What has to happen to the concentrations of the reactants in order to maintain the value of K?